b^2=12(b-3)

Solution for b^2=12(b-3) equation:

Simplifying
b2 = 12(b + -3)

Reorder the terms:
b2 = 12(-3 + b)
b2 = (-3 * 12 + b * 12)
b2 = (-36 + 12b)

Solving
b2 = -36 + 12b

Solving for variable 'b'.

Reorder the terms:
36 + -12b + b2 = -36 + 12b + 36 + -12b

Reorder the terms:
36 + -12b + b2 = -36 + 36 + 12b + -12b

Combine like terms: -36 + 36 = 0
36 + -12b + b2 = 0 + 12b + -12b
36 + -12b + b2 = 12b + -12b

Combine like terms: 12b + -12b = 0
36 + -12b + b2 = 0

Factor a trinomial.
(6 + -1b)(6 + -1b) = 0

Subproblem 1
Set the factor '(6 + -1b)' equal to zero and attempt to solve:

Simplifying
6 + -1b = 0

Solving
6 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -1b = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -1b = 0 + -6
-1b = 0 + -6

Combine like terms: 0 + -6 = -6
-1b = -6

Divide each side by '-1'.
b = 6

Simplifying
b = 6
Subproblem 2
Set the factor '(6 + -1b)' equal to zero and attempt to solve:

Simplifying
6 + -1b = 0

Solving
6 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -1b = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -1b = 0 + -6
-1b = 0 + -6

Combine like terms: 0 + -6 = -6
-1b = -6

Divide each side by '-1'.
b = 6

Simplifying
b = 6
Solution
b = {6, 6}